Integrand size = 21, antiderivative size = 45 \[ \int \frac {\sin ^3(a+b x)}{(d \cos (a+b x))^{11/2}} \, dx=\frac {2}{9 b d (d \cos (a+b x))^{9/2}}-\frac {2}{5 b d^3 (d \cos (a+b x))^{5/2}} \]
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Time = 0.04 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {2645, 14} \[ \int \frac {\sin ^3(a+b x)}{(d \cos (a+b x))^{11/2}} \, dx=\frac {2}{9 b d (d \cos (a+b x))^{9/2}}-\frac {2}{5 b d^3 (d \cos (a+b x))^{5/2}} \]
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Rule 14
Rule 2645
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Subst}\left (\int \frac {1-\frac {x^2}{d^2}}{x^{11/2}} \, dx,x,d \cos (a+b x)\right )}{b d} \\ & = -\frac {\text {Subst}\left (\int \left (\frac {1}{x^{11/2}}-\frac {1}{d^2 x^{7/2}}\right ) \, dx,x,d \cos (a+b x)\right )}{b d} \\ & = \frac {2}{9 b d (d \cos (a+b x))^{9/2}}-\frac {2}{5 b d^3 (d \cos (a+b x))^{5/2}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(94\) vs. \(2(45)=90\).
Time = 0.37 (sec) , antiderivative size = 94, normalized size of antiderivative = 2.09 \[ \int \frac {\sin ^3(a+b x)}{(d \cos (a+b x))^{11/2}} \, dx=\frac {2 \left (4 \sqrt [4]{\cos ^2(a+b x)}+\left (9-8 \sqrt [4]{\cos ^2(a+b x)}\right ) \csc ^2(a+b x)+4 \left (-1+\sqrt [4]{\cos ^2(a+b x)}\right ) \csc ^4(a+b x)\right ) \tan ^4(a+b x)}{45 b d^5 \sqrt {d \cos (a+b x)}} \]
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Time = 0.05 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.82
method | result | size |
derivativedivides | \(\frac {-\frac {2}{5 \left (d \cos \left (b x +a \right )\right )^{\frac {5}{2}}}+\frac {2 d^{2}}{9 \left (d \cos \left (b x +a \right )\right )^{\frac {9}{2}}}}{b \,d^{3}}\) | \(37\) |
default | \(\frac {-\frac {2}{5 \left (d \cos \left (b x +a \right )\right )^{\frac {5}{2}}}+\frac {2 d^{2}}{9 \left (d \cos \left (b x +a \right )\right )^{\frac {9}{2}}}}{b \,d^{3}}\) | \(37\) |
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Time = 0.30 (sec) , antiderivative size = 38, normalized size of antiderivative = 0.84 \[ \int \frac {\sin ^3(a+b x)}{(d \cos (a+b x))^{11/2}} \, dx=-\frac {2 \, \sqrt {d \cos \left (b x + a\right )} {\left (9 \, \cos \left (b x + a\right )^{2} - 5\right )}}{45 \, b d^{6} \cos \left (b x + a\right )^{5}} \]
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Timed out. \[ \int \frac {\sin ^3(a+b x)}{(d \cos (a+b x))^{11/2}} \, dx=\text {Timed out} \]
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Time = 0.20 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.82 \[ \int \frac {\sin ^3(a+b x)}{(d \cos (a+b x))^{11/2}} \, dx=-\frac {2 \, {\left (9 \, d^{2} \cos \left (b x + a\right )^{2} - 5 \, d^{2}\right )}}{45 \, \left (d \cos \left (b x + a\right )\right )^{\frac {9}{2}} b d^{3}} \]
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\[ \int \frac {\sin ^3(a+b x)}{(d \cos (a+b x))^{11/2}} \, dx=\int { \frac {\sin \left (b x + a\right )^{3}}{\left (d \cos \left (b x + a\right )\right )^{\frac {11}{2}}} \,d x } \]
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Time = 5.09 (sec) , antiderivative size = 279, normalized size of antiderivative = 6.20 \[ \int \frac {\sin ^3(a+b x)}{(d \cos (a+b x))^{11/2}} \, dx=\frac {16\,{\mathrm {e}}^{a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}\,\sqrt {d\,\left (\frac {{\mathrm {e}}^{-a\,1{}\mathrm {i}-b\,x\,1{}\mathrm {i}}}{2}+\frac {{\mathrm {e}}^{a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}}{2}\right )}}{5\,b\,d^6\,{\left ({\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}+1{}\mathrm {i}\right )}^2}-\frac {{\mathrm {e}}^{a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}\,\sqrt {d\,\left (\frac {{\mathrm {e}}^{-a\,1{}\mathrm {i}-b\,x\,1{}\mathrm {i}}}{2}+\frac {{\mathrm {e}}^{a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}}{2}\right )}\,464{}\mathrm {i}}{45\,b\,d^6\,{\left ({\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}+1{}\mathrm {i}\right )}^3}-\frac {128\,{\mathrm {e}}^{a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}\,\sqrt {d\,\left (\frac {{\mathrm {e}}^{-a\,1{}\mathrm {i}-b\,x\,1{}\mathrm {i}}}{2}+\frac {{\mathrm {e}}^{a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}}{2}\right )}}{9\,b\,d^6\,{\left ({\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}+1{}\mathrm {i}\right )}^4}+\frac {{\mathrm {e}}^{a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}\,\sqrt {d\,\left (\frac {{\mathrm {e}}^{-a\,1{}\mathrm {i}-b\,x\,1{}\mathrm {i}}}{2}+\frac {{\mathrm {e}}^{a\,1{}\mathrm {i}+b\,x\,1{}\mathrm {i}}}{2}\right )}\,64{}\mathrm {i}}{9\,b\,d^6\,{\left ({\mathrm {e}}^{a\,2{}\mathrm {i}+b\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}+1{}\mathrm {i}\right )}^5} \]
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